Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $5x^{2} - 6x + 2 = 0$.

(D) For a quadratic equation of the form $ax^{2} + bx + c = 0$,the discriminant $D$ is given by $D = b^{2} - 4ac$.
Here,$a = 5$,$b = -6$,and $c = 2$.
Substituting these values into the formula: $D = (-6)^{2} - 4(5)(2)$.
$D = 36 - 40 = -4$.
Since the discriminant $D < 0$,the equation has no real roots.